A and B move towards each other at the same time at the speeds of 10 km/h and 20 km/h, respectively and the distance between them is 49 km. How much is the distance between them, in m, 5 minutes before they meet?

2500

Speed of A = 10 km/hr

And speed of B = 20 km/hr

Relative speed(when moves in opposite direction) = 10 + 20 = 30 km/hr

Now, distance covered in 60 mins = 30 km

So, distance covered in 5 mins =  \(\frac{30}{60}\) × 5  km

= 2.5 km = 2500 m

So , The distance between them 5 min before they meet is 2500 m