If a wire of resistance 20Ω is covered with ice (at 0°C) and a voltage of 210 V is applied across the wire, then the rate of melting of ice is:

0.85 gs-1 1.92 gs-1 6.59 gs-1 none of these

6.59 gs-1

$\frac{dm}{dt}=\frac{\left(V^2 / R\right)}{L}=\frac{(210)^2 / 20}{80 \times 4.18}$ = 6.59 gs-1