A person has to cover a distance of 320 km in 20 hours.  If he covers \(\frac{3}{5}\)th of the distance in \(\frac{1}{2}\) of the time, then what should be his speed (in km/h) to cover the remaining distance in the remaining time?

19.2 km/h

\(\frac{2}{5}\) of 320 = 128 km

Remaining distance = 192 km

\(\frac{1}{2}\) of time = \(\frac{1}{2}\) × 20 = 10 hours

Remaining hours = 10 hours

Speed for the remaining distance = \(\frac{192}{10}\) = 19.2 km/h