Practicing Success
Practicing Success
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If the time of revolution of a satellite is T, then the potential energy will be proportional to : |
\(T^{-2/3}\) \(\frac{1}{T}\) \(\frac{1}{T^2}\) \(\frac{1}{T^3}\) |
\(T^{-2/3}\) |
Velocity of satellite : \(v = \sqrt{\frac{GM}{r}}\) Kinetic Energy : \(K.E. \propto v^2 \text{ and } v^2 \propto \frac{1}{r}\) Also, Time period square: \(T^2 = r^3\) \(\Rightarrow K.E. \propto T^{-2/3}\) |
