Find the domain of function $f(x)= \sin(\log_e(\frac{\sqrt{4-x^2}}{1-x}))$
Answer & explanation
Correct answer: option 1
We have $f(x)= \sin(\log_e(\frac{\sqrt{4-x^2}}{1-x}))$
We must have $4-x^2> 0$ and $1-x>0$
$⇒x^2<4$ and $x<1$
$⇒-2 < x <2$ and $x<1$
$⇒-2 < x < 1$
Thus, domain of f(x) is (-2, 1)