The energy of a photon corresponding to the visible light of maximum wavelength is approximately
Answer & explanation
Correct answer: option 2
$E=\frac{12400}{λ(Å)}eV$
$E=\frac{12400}{8000Å}=1.6eV$
The energy of a photon corresponding to the visible light of maximum wavelength is approximately
Correct answer: option 2
$E=\frac{12400}{λ(Å)}eV$
$E=\frac{12400}{8000Å}=1.6eV$