An electric bulb rated 220 v and 60 W is connected in series with another electric bulb rated 220 v and 40 W. The combination is connected across 220 volt source of e.m.f. Which of the following statement is true?

$ P_1'> P_2'$

$\text{ Since the two bulbs are in series hence current through both are same}$

$ P_1'= I^2 R_1 = I^2 \frac{V^2}{P_1}$

$ P_2'= I^2 R_2 = I^2 \frac{V^2}{P_2}$

$\frac{P_2'} {P_1'} = \frac{P_2}{P_1} < 1$

$ P_2'<P_1'$

The bulb rated 220 V & 40 W will glow more.