If x2 - 5x - 1 = 0, what is the value of (x^6-x^4+x^2-1)/(x^3) ?

If x² - 5x - 1 = 0

x - \(\frac{1}{x}\) = 5

x³ - \(\frac{1}{x^3}\) = 5³ + 3 × 5 = 140

$\frac{x^6-x^4+x^2-1}{x^3}$ = x³ - \(\frac{1}{x^3}\) - (x - \(\frac{1}{x}\))

= 140 - 5 = 135