A train is to cover 370 km at a uniform speed. After running 100 km, the train could run at a speed 5 km/h less than its normal speed due to some technical fault. The train got delayed by 36 minutes. What is the normal speed of the train, in km/h ?

50

Let speed of train = S km/h

According to question ,

[ \(\frac{100}{S}\) - \(\frac{270}{S - 5 }\) ] - \(\frac{370}{S}\)  = \(\frac{36}{60}\)

\(\frac{270}{S-5}\) - \(\frac{270}{S}\) = \(\frac{3}{5}\)

\(\frac{1}{S-5}\) - \(\frac{1}{S}\) = \(\frac{1}{450}\)

On solving it ,

S = 50 km/h

So , Speed of train is 50 km/h