Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

The density of a nucleus of mass number A is proportional to:

Options:

$A^3$

$A^{1 / 3}$

$A^1$

$A^0$

Correct Answer:

$A^0$

Explanation:

The correct answer is Option (4) → $A^0$

R, Radius of Nucleus = $R_oA^{1/3}$ [A → mass number]

∴ v, volume of nucleus = $(R_oA^{1/3})^3=R_oA$

ρ, density of nucleus = $\frac{Mass}{Volume}=\frac{1}{R_o}$ = Constant

$∝A^0$