The density of a nucleus of mass number A is proportional to: |
$A^3$ $A^{1 / 3}$ $A^1$ $A^0$ |
$A^0$ |
The correct answer is Option (4) → $A^0$ R, Radius of Nucleus = $R_oA^{1/3}$ [A → mass number] ∴ v, volume of nucleus = $(R_oA^{1/3})^3=R_oA$ ρ, density of nucleus = $\frac{Mass}{Volume}=\frac{1}{R_o}$ = Constant $∝A^0$ |