The density of a nucleus of mass number A is proportional to:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $A^0$
R, Radius of Nucleus = $R_oA^{1/3}$ [A → mass number]
∴ v, volume of nucleus = $(R_oA^{1/3})^3=R_oA$
ρ, density of nucleus = $\frac{Mass}{Volume}=\frac{1}{R_o}$ = Constant
$∝A^0$