The number of moles of NaOH present in 10 L of a 1 M solution is:

The correct answer is Option (1) → 10

Molarity is the number of moles of solute in one litre of solution, so the moles of solute are molarity × volume in litres:

    \( \displaystyle \text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution in litre}} \)

    \( \displaystyle \text{Moles of NaOH}=1\,\mathrm{mol\,L^{-1}}\times10\,\mathrm{L} \)

    \( \displaystyle \text{Moles of NaOH}=10\,\mathrm{mol} \)