Match List I with List II

Choose the correct answer from the options given below:

A-III, B-IV, C-II, D-I

The correct answer is option 2.  A-III, B-IV, C-II, D-I.

A. Gatterman-Koch reaction → III. Benzaldehyde

In this reaction, Benzene is treated with Carbon monoxide $(CO)$ and Hydrogen chloride $(HCl)$ in the presence of anhydrous $AlCl_{3}$ or $CuCl$. This introduces a formyl group $(-CHO)$ directly onto the ring.

B. Stephen's reaction → IV. Acetaldehyde

This is a reduction of nitriles. Methyl cyanide $(CH_{3}CN)$ is reduced using stannous chloride $(SnCl_{2})$ and $HCl$, followed by hydrolysis, to yield Acetaldehyde.

C. Hoffmann Bromamide degradation → II. Ethyl amine

This reaction converts an amide into a primary amine with one less carbon atom. If you start with Propanamide $(CH_{3}CH_{2}CONH_{2})$ and treat it with Bromine $(Br_{2})$ and $KOH$, the carbonyl group is removed, leaving you with Ethyl amine $(CH_{3}CH_{2}NH_{2})$.

D. Fittig reaction → I. Diphenyl

The Fittig reaction involves the treatment of haloarenes (like Chlorobenzene) with metallic Sodium in dry ether. Two aryl groups join together to form a diaryl compound, in this case, Diphenyl (also known as Biphenyl).