Practicing Success
Let [.] denote the greatest integer function and $f (x) = [\tan^2x]$. Then, |
$\underset{x→0}{\lim}f(x)$ does not exist f (x) is continuous at x = 0 f (x) is not differentiable at x = 0 f'(0) = 1 |
f (x) is continuous at x = 0 |
We have $f (0) = [\tan^2 0] = [0] = 0$, $f(0+0)=\underset{x→0}{\lim}f(x)=\underset{h→0}{\lim}[\tan^2(0+h)]$, where h is positive and sufficiently small $=\underset{h→0}{\lim}[\tan^2h]=\underset{h→0}{\lim}0=0$ and $f(0+0)=\underset{x→0^-}{\lim}f(x)=\underset{h→0}{\lim}[\tan^2(0-h)]$, where h is positive and sufficiently small $=\underset{h→0}{\lim}[\tan^2h]=\underset{h→0}{\lim}0=0$ Since f(0 − 0) = f(0) = f(0 + 0), therefore f(x) is continuous at x = 0. |