Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

Let [.] denote the greatest integer function and $f (x) = [\tan^2x]$. Then,

Options:

$\underset{x→0}{\lim}f(x)$ does not exist

f (x) is continuous at x = 0

f (x) is not differentiable at x = 0

f'(0) = 1

Correct Answer:

f (x) is continuous at x = 0

Explanation:

We have $f (0) = [\tan^2 0] = [0] = 0$,

$f(0+0)=\underset{x→0}{\lim}f(x)=\underset{h→0}{\lim}[\tan^2(0+h)]$, where h is positive and sufficiently small

$=\underset{h→0}{\lim}[\tan^2h]=\underset{h→0}{\lim}0=0$

and $f(0+0)=\underset{x→0^-}{\lim}f(x)=\underset{h→0}{\lim}[\tan^2(0-h)]$, where h is positive and sufficiently small

$=\underset{h→0}{\lim}[\tan^2h]=\underset{h→0}{\lim}0=0$

Since f(0 − 0) = f(0) = f(0 + 0), therefore f(x) is continuous at x = 0.