If every element of a third order determinant of value Δ is multiplied by 5, then the value of new determinant, is

Δ 5Δ 25Δ 125Δ

125Δ

Let $A=[a_{ij}]$ be a square matrix of order n, then $|kA|=k^n|A|$ we get value of new determinant as $5^3Δ=125Δ$