CUET Preparation Today
If every element of a third order determinant of value Δ is multiplied by 5, then the value of new determinant, is |
Δ 5Δ 25Δ 125Δ |
125Δ |
Let $A=[a_{ij}]$ be a square matrix of order n, then $|kA|=k^n|A|$ we get value of new determinant as $5^3Δ=125Δ$ |
