Practicing Success
For what value of a and b, the equation $\int(\sin 2 x-\cos 2 x) d x=\frac{1}{\sqrt{2}} \sin (2 x-a)+b$ holds good? |
a = $-\frac{5 \pi}{4}$, b is any arbitrary constant a = $\frac{5 \pi}{4}$, b any arbitrary constant a = $-\frac{\pi}{4}$, b any arbitrary constant a = $\frac{\pi}{4}$, b any arbitrary constant |
a = $-\frac{5 \pi}{4}$, b is any arbitrary constant |
$\int(\sin 2 x-\cos 2 x) d x$ $=-\int \sqrt{2} \cos \left(2 x+\frac{\pi}{4}\right) d x$ $=\frac{-\sqrt{2}}{2} \sin \left(2 x+\frac{\pi}{4}\right)+c=\frac{1}{\sqrt{2}} \sin \left(2 x+\frac{5 \pi}{4}\right)+c$ a = $-\frac{5 \pi}{4}$, b is any arbitrary constant Hence (1) is the correct answer. |