Practicing Success

Target Exam

CUET

Subject

Biology

Chapter

Molecular Basis of Inheritance

Question:

Match the Column 1 with Column 2 :

 Column1   Column 2
1) z gene a)   Permease
2) y gene b)  Transacetylase. 
3) a gene c)  Repressor
4) i gene  d)  Beta-galactosidase (β-gal)

 

Options:

1-d,2-a,3-c,4-b .

1-d,2-a,3-b,4-c .

1-d,2-b,3-a,4-c .

1-a,2-d,3-b,4-c .

Correct Answer:

1-d,2-a,3-b,4-c .

Explanation:

The correct answer is Option (2) - 1-d,2-a,3-b,4-c.

 Column1   Column 2
1) z gene d)  Beta-galactosidase (β-gal)
2) y gene a)   Permease
3) a gene b)  Transacetylase.
4) i gene  c)  Repressor

The lac operon consists of one regulatory gene (the i gene – here the term i does not refer to inducer, rather it is derived from the word inhibitor) and three structural genes (z, y, and a). The i gene codes for the repressor of the lac operon. The z gene codes for beta-galactosidase ( β-gal), which is primarily responsible for the hydrolysis of the disaccharide, lactose into its monomeric units, galactose and glucose. The y gene codes for permease, which increases permeability of the cell to β-galactosides. The a gene encodes a transacetylase. Hence, all the three gene products in lac operon are required for metabolism of lactose