Practicing Success
Practicing Success
CUET Preparation Today
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a b c d |
b |
$\text{From time t = 0 to } t= t_0 \text{ growth of current takes place}$ $ I = I_0 (1- e^-\frac{t}{\tau})$ $ \text{After t= } t_0 , I = I_{max} e^-\frac{t}{\tau}$ $\text{Only option b is correct representation}$ |
