Let $ \triangle ABC \sim \triangle RPQ$ and $\frac{ar(\triangle ABC)}{ar(\triangle PQR)}=\frac{4}{9}$. If AB = 3cm, BC = 4cm, and AC = 5cm, then RP (In cm )is equal to :
Answer & explanation
Correct answer: option 3
\(\Delta \)ABC is similar to \(\Delta \)RPQ
\(\frac{AB}{RP}\) = \(\sqrt {4/9 }\)
RP = \(\frac{3}{2}\) x 3 = (As AB = 3)
RP = 4.5