The angles of elevation of the top of a tower from two points at a distance of 5 meters and 20 meters along the same straight line from the base of the tower, are complementary. Find the height of the tower. |
10 m 15 m $10\sqrt{3} m$ 20 m |
10 m |
The correct answer is Option (1) → 10 m Step 1: Let the height of the tower be h
Step 2: Use tangent formula $\tan \theta = \frac{h}{5}$ $\tan(90^\circ - \theta) = \frac{h}{20} ⟹\cot \theta = \frac{h}{20} ⟹ \frac{1}{\tan \theta} = \frac{h}{20} ⟹ \tan \theta = \frac{20}{h}$ Step 3: Equate $\tan \theta$ $\frac{h}{5} = \frac{20}{h}$ $h^2 = 100$ $h = 10 \text{ m}$ |