CUET Preparation Today
CUET
Physics
Current Electricity
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$ \frac{R}{l} = \frac{\rho}{ A }=\frac{4\times 10^{-7}}{ 8\times 10^{-6}}= 0.05 \Omega/m$
$ \text{Potential Gradient }\frac{V}{l} = \frac{IR}{l} = 25mV/m$
