CUET Preparation Today
Hybridisation state of central metal ion in [Fe(NH3)4(en)]2+ will be |
sp3 dsp2 d2sp3 sp3d2 |
d2sp3 |
In [Fe(NH3)4(en)]2+ x + 4(0) + 1(0) = 2 x = 2 26Fe: [Ar]4s23d6 Fe2+: [Ar]3d6
In presence of strong field ligand,
six donor atoms will use d2sp3 hybrid orbitals and hybridization of central metal ion will be d2sp3. |
