If x3 + y3 = 1339 x + y = 13 Find the value of xy.

11 22 33 44

22

x3 + y3 = 1339 x + y = 13 (x + y)3 = x3 + y3 + 3xy (x + y) 2197 = 1339 + 39xy xy = \(\frac{858}{39}\) xy = 22