Two slits are made 1 mm apart and the screen is placed 1 m away. What is the fringe width when a light used of wavelength 500 nm?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 0.5 mm
In young's double slit experiment,
$β=\frac{λL}{D}$
$=\frac{500×10^{-9}×1}{1×10^{-3}}=0.5mm$