The area (in sq.units) of the region bounded by the curve $y = \cos x$ between $x = -\frac{\pi}{2},x=\frac{\pi}{2}$ and the x-axis is

2

The correct answer is Option (3) → 2

Area = $\displaystyle\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\cos x\,dx$

$=\bigl[\sin x\bigr]_{-\frac{\pi}{2}}^{\frac{\pi}{2}}=\sin\frac{\pi}{2}-\sin\left(-\frac{\pi}{2}\right)=1-(-1)=2$

The area of the region is $2$ square units.