Find the area of a trapezium whose parallel sides are of length 15 cm and 20 cm, respectively, and whose distance between the parallel sides is 12 cm. |
360 cm2 280 cm2 120 cm2 210 cm2 |
210 cm2 |
We know that, Area of a trapezium = \(\frac{1}{2}\) × (Sum of the length of the parallel sides) × (Distance between two parallel side) We have, The length of the parallel sides of the trapezium = 15 cm and 20 cm. The between the parallel sides = 12 cm. Area of the trapezium = \(\frac{1}{2}\) × (15 + 20) × 12 = 35 × 6 = 210 cm2 |