The value of $\frac{(2.7)^3-(2.2)^3}{(2.7)^2+2.7×2.2+(2.2)^2}$ is
Answer & explanation
Correct answer: option 2
Here, we use the formula: $a^3 - b^3 = (a - b)(a^2 + ab +b^2)$
Now, put this formula in numerator:
$\frac{(2.7)^3-(2.2)^3}{(2.7)^2+2.7×2.2+(2.2)^2}$ = $\frac{(2.7 - 2.2)((2.7)^2+2.7×2.2+(2.2)^2)}{(2.7)^2+2.7×2.2+(2.2)^2}$
= (2.7 - 2.2)
= 0.5