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The value of $\frac{(2.7)^3-(2.2)^3}{(2.7)^2+2.7×2.2+(2.2)^2}$ is |
4.9 0.5 0.05 0.49 |
0.5 |
Here, we use the formula: $a^3 - b^3 = (a - b)(a^2 + ab +b^2)$ Now, put this formula in numerator: $\frac{(2.7)^3-(2.2)^3}{(2.7)^2+2.7×2.2+(2.2)^2}$ = $\frac{(2.7 - 2.2)((2.7)^2+2.7×2.2+(2.2)^2)}{(2.7)^2+2.7×2.2+(2.2)^2}$ = (2.7 - 2.2) = 0.5
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