If $x + \frac{1}{3x} = 5, $ then the value of $27x^3 +\frac{1}{x^3}$ will be :
Answer & explanation
Correct answer: option 1
If $x + \frac{1}{3x} = 5, $
then the value of $27x^3 +\frac{1}{x^3}$ will be = ?
If $K+\frac{1}{K}=n$
then, $K^3+\frac{1}{K^3}$ = n3 – 3 × k × \(\frac{1}{k}\)
If $x + \frac{1}{3x} = 5, $
Then $x^3 +\frac{1}{27x^3}$ = 53 – 3 × 5 ÷ 3 = 120
Multiply the whole equation by 27 to get the desired form of equation,
and the value of $27x^3 +\frac{1}{x^3}$ = 120 × 27 = 3240