The magnetic field in a travelling electromagnetic wave has a peak value of 30 nT. The peak value of electric field strength is: (speed of light in free space is $3 \times 10^8 m/s$).
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 9.0 V/m
$E_{max}=cB_{max}$
Where,
$E_{max}$ = Peak value of electric field
$B_{max}$ = Peak value of magnetic field
$c = 3×10^8m/s$ (Speed of light)
$E_{max}=(3×10^8)(30×10^{-9})$
$=9V/m$