A well with 14 m inside diameter is dug 10 m deep. Earth taken out of it has been evenly spread all round it to a width of 5 m form an embankment, then height if the embankment will be : |
1 m \(\frac{98}{15}\) m $\frac{4}{3}$ m 2 m |
\(\frac{98}{15}\) m |
Radius = 14/2 = 7 m Volume = πr²h = \(\frac{22}{7}\) × 7 ×7 ×10 = 1540 It is taken out and spread width of 21m , R2 = (5 + 5 = 10 m ) V = \(\frac{22}{7}\) × ( R² - r²)h 1540 = \(\frac{22}{7}\) × ( 10² - 5²) h 1540 = \(\frac{22}{7}\) × ( ( 10² - 5²) h 490 = ( 75) h h = \(\frac{98}{15}\) The correct answer is option (2) : \(\frac{98}{15}\) m |