Practicing Success
CUET Preparation Today
CUET
Physics
Alternating Current
a
b
c
d
RMS value of current $I_{rms}^2 = \frac{\int_{0}^{T}t^4 dt}{T} = \frac{T^4}{5}$
$I_{rms} = \frac{T^2}{\sqrt 5}$