Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

Options:

a

b

c

d

Correct Answer:

c

Explanation:

RMS value of current $I_{rms}^2 = \frac{\int_{0}^{T}t^4 dt}{T} = \frac{T^4}{5}$

$I_{rms} = \frac{T^2}{\sqrt 5}$