Two cards are drawn one by one from a pack of cards. The probability of getting first card an ace and second an honour card is (before drawing second card first card is not placed again in the pack)

$\frac{5}{221}$

$P(E_1)=\frac{4}{52}=\frac{1}{13}, P\left(\frac{E_2}{E_1}\right) = \frac{15}{51}=\frac{5}{17}$

$P(E_1 ∩ E_2) = P(E_1).P \left(\frac{E_2}{E_1}\right)=\frac{1}{13}.\frac{5}{13}=\frac{5}{221}.$