Two cards are drawn one by one from a pack of cards. The probability of getting first card an ace and second an honour card is (before drawing second card first card is not placed again in the pack)
Answer & explanation
Correct answer: option 3
$P(E_1)=\frac{4}{52}=\frac{1}{13}, P\left(\frac{E_2}{E_1}\right) = \frac{15}{51}=\frac{5}{17}$
$P(E_1 ∩ E_2) = P(E_1).P \left(\frac{E_2}{E_1}\right)=\frac{1}{13}.\frac{5}{13}=\frac{5}{221}.$