If 4x2 + 3y2 = 48 , xy = 6 (x, y > 0)
find 3x3 + y2.
Answer & explanation
Correct answer: option 1
By Putting x = 3 and y = 2
These values are satisfying the equations:
⇒ 4x2 + 3y2 = 48
⇒ 4(3)2 + 3(2)2 = 48
⇒ 48 = 48
Put these values and find:
⇒ 3x3 + y2 = 3(3)3 + (2)2= 81 + 4 = 85