The population of a town is increasing at the rate of 10% per year. If the present population of the town is 1,00,000, what will its population be 2 years from now?
Answer & explanation
Correct answer: option 2
Present population = 1,00,000
Increased Population = 100000 × \(\frac{100+10}{100}\) × \(\frac{100+10}{100}\)
= 100000 × \(\frac{110}{100}\) × \(\frac{110}{100}\)
= 121000
So , Increased Population = 121000