To a circle with center at O, two tangents AP and AQ are drawn from an external point A, if the ∠PAQ = 113 degree, then the ∠POQ is?

67° 113° 247° 95°

67°

In APOQ ∠OPA = ∠OQA = 90° (tangents) Therefore, ∠POQ = 180° - ∠A ∠POQ = 180° - 113° = 67°