If $f: R→R$ is defined by $f(x) = (4-x^2)^{\frac{1}{2}},$ then $fof(x)$ is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $|x|$
$f(x)=(4-x^2)^{\frac{1}{2}}$
So $fof(x)=\left(4-\left(\left(4-x^2\right))^{\frac{1}{2}}\right)^2\right)^{\frac{1}{2}}$
$=\left(4-4+x^2\right)^{\frac{1}{2}}$
$=|x|$