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If $f: R→R$ is defined by $f(x) = (4-x^2)^{\frac{1}{2}},$ then $fof(x)$ is : |
$|x|$ $2|x|$ $x^2 $ 0 |
$|x|$ |
The correct answer is Option (1) → $|x|$ $f(x)=(4-x^2)^{\frac{1}{2}}$ So $fof(x)=\left(4-\left(\left(4-x^2\right))^{\frac{1}{2}}\right)^2\right)^{\frac{1}{2}}$ $=\left(4-4+x^2\right)^{\frac{1}{2}}$ $=|x|$ |
