Working together A, B and C can complete a piece of work in 3 days. A completes the same work in 24 days and B completes it in 6 days. How many days will C alone take to complete the same work?

8

A + B + C = 3 days,

A = 24 days, 

B = 6 days, 

⇒ A + B + C = 8,   (Efficiency)

⇒ 1 + 4 + C = 8,

⇒ C = 8 - 5

⇒ C = 3,

⇒ Time required by C to complete the work alone = \(\frac{24}{3}\) = 8 days,  ..(\(\frac{Work}{Efficiency}\) = Time)