If \(\sqrt {2 }\)sin3θ = 1 , then find the value of θ

18° 20° 15° 10°

15°

If  \(\sqrt {2 }\)sin3θ = 1  sin3θ = \(\frac{1}{√2}\)       [sin45°=\(\frac{1}{√2}\)] sin3θ = sin45° 3θ = 45° θ=\(\frac{45°}{3}\) θ =15°