If \(\sqrt {2 }\)sin3θ = 1 , then find the value of θ
Answer & explanation
Correct answer: option 3
If \(\sqrt {2 }\)sin3θ = 1
sin3θ = \(\frac{1}{√2}\) [sin45°=\(\frac{1}{√2}\)]
sin3θ = sin45°
3θ = 45°
θ=\(\frac{45°}{3}\)
θ =15°
If \(\sqrt {2 }\)sin3θ = 1 , then find the value of θ
Correct answer: option 3
If \(\sqrt {2 }\)sin3θ = 1
sin3θ = \(\frac{1}{√2}\) [sin45°=\(\frac{1}{√2}\)]
sin3θ = sin45°
3θ = 45°
θ=\(\frac{45°}{3}\)
θ =15°