The sum of 17 consecutive numbers is 289. The sum of another 10 consecutive numbers, whose first term is 5 more than the average of the first set of consecutive numbers, is:

265

Average of 17 terms = \(\frac{289}{17}\) = 17

First term of another 10 consecutive number = 17 + 5 = 22

So , Next series is  22 , 23 , 24 , 25 , 26 , 27 , 28 , 29 , 30 , 31 \

Sum of these 10 numbers = \(\frac{n}{2}\)(a+l)

= \(\frac{10}{2}\) ×  (22+31) = 5 × 53 = 265