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If $2x^2 - 6x = 1,$ then $x^2 + \frac{1}{4x^2} = ?$ |
8 12 9 10 |
10 |
We know that, If $K-\frac{1}{K}=n$ then, $K^2+\frac{1}{K^2}$ = n2 + 2 If $2x^2 - 6x = 1,$ $x^2 + \frac{1}{4x^2} = ?$ Divide both sides by 2x on If $2x^2 - 6x = 1,$ we get, x - \(\frac{1}{2x}\) = 3 and $x^2 + \frac{1}{4x^2}$ = 32 + 2 × \(\frac{1}{2}\) = 9 + 1 = 10 |
