If $2x^2 - 6x = 1,$ then $x^2 + \frac{1}{4x^2} = ?$
Answer & explanation
Correct answer: option 4
We know that,
If $K-\frac{1}{K}=n$
then, $K^2+\frac{1}{K^2}$ = n2 + 2
If $2x^2 - 6x = 1,$
$x^2 + \frac{1}{4x^2} = ?$
Divide both sides by 2x on If $2x^2 - 6x = 1,$ we get,
x - \(\frac{1}{2x}\) = 3
and $x^2 + \frac{1}{4x^2}$ = 32 + 2 × \(\frac{1}{2}\) = 9 + 1 = 10