If $\begin{vmatrix}2&3-x\\x&1\end{vmatrix}=0$, then the values of $x$ are:

1 and 3 1 and 2 2 and 3 3 and 0

1 and 2

$\begin{vmatrix}2&3-x\\x&1\end{vmatrix}=0$ $⇒2×1-(3-x)(x)$ $⇒2-3x+x^2=0$ $⇒x^2-3x+2=0⇒x^2-2x-x+2=0$ $⇒x(x-2)-1(x-2)=0⇒(x-1)(x-2)=0$ $⇒x=1,2$