If $\begin{vmatrix}2&3-x\\x&1\end{vmatrix}=0$, then the values of $x$ are:
Answer & explanation
Correct answer: option 2
$\begin{vmatrix}2&3-x\\x&1\end{vmatrix}=0$
$⇒2×1-(3-x)(x)$
$⇒2-3x+x^2=0$
$⇒x^2-3x+2=0⇒x^2-2x-x+2=0$
$⇒x(x-2)-1(x-2)=0⇒(x-1)(x-2)=0$
$⇒x=1,2$