The degree of the differential equation $\left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^{3/2} = \frac{d^2y}{dx^2}$ is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 2 ##
Given that $\left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^{3/2} = \frac{d^2y}{dx^2}$
On squaring both sides, we get
$\left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^3 = \left( \frac{d^2y}{dx^2} \right)^2$
The highest order derivative is $\frac{d^2y}{dx^2}$ and the highest power raised to $\frac{d^2y}{dx^2}$ is 2.
So, the degree of differential equation is 2.