If x - y + z = 0
find \(\frac{{y}^{2}}{2xz}\) - \(\frac{{x}^{2}}{2yz}\) - \(\frac{{z}^{2}}{2xy}\)
Answer & explanation
Correct answer: option 1
Put x = z = 1
and y = 2
= \(\frac{{y}^{2}}{2xz}\) - \(\frac{{x}^{2}}{2yz}\) - \(\frac{{z}^{2}}{2xy}\)
= \(\frac{4}{2}\) - \(\frac{1}{4}\) - \(\frac{1}{4}\)
= \(\frac{3}{2}\)