CUET Preparation Today
The point on the curve $y^2=x$ where tangent makes 45° angle with x-axis is: |
$\left(\frac{1}{2}, \frac{1}{4}\right)$ $\left(\frac{1}{4}, \frac{1}{2}\right)$ $(4,2)$ $(1,1)$ |
$\left(\frac{1}{4}, \frac{1}{2}\right)$ |
The correct answer is Option (2) - $\left(\frac{1}{4}, \frac{1}{2}\right)$ |
