Area of region bounded by the curve $y^2=4 x$, y-axis and the line y = 3 is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{9}{4}$
$y^2=4x$
so $x=\frac{y^2}{4}$
⇒ required area = $\int\limits_0^3\frac{y^2}{4}dy$
$⇒\left[\frac{y^3}{12}\right]_0^3$
$=\frac{9}{4}$ sq. units