50 capacitors each of capacitance 'C' are connected as shown in figure. Calculate the equivalent capacitance between the point 'A' and 'B'.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{50}{49} C$
As 49 capacitor are connected in series
$\frac{1}{C_{eq}}=\frac{1}{C}+\frac{1}{C}+.....+\frac{1}{C}$ [4 times]
$C_{eq}=\frac{C}{49}$
and,
And as these two capacitor are connected in parallel to each other,
$C_{res}=C+\frac{C}{49}=\frac{50C}{49}$