50 capacitors each of capacitance 'C' are connected as shown in figure. Calculate the equivalent capacitance between the point 'A' and 'B'.

$\frac{50}{49} C$

The correct answer is Option (3) → $\frac{50}{49} C$

As 49 capacitor are connected in series

$\frac{1}{C_{eq}}=\frac{1}{C}+\frac{1}{C}+.....+\frac{1}{C}$ [4 times]

$C_{eq}=\frac{C}{49}$

and,

And as these two capacitor are connected in parallel to each other,

$C_{res}=C+\frac{C}{49}=\frac{50C}{49}$