CUET Preparation Today
If $sin^2 x = 3 cos^2 x $ and 0° ≤ x ≤ 90°, then what is the value of $\frac{x}{2}$ ? |
22.5° 45° 15° 30° |
30° |
sin²x = 3cos²x tan²x = 3 tanx = \(\sqrt {3 }\) { tan 60º = \(\sqrt {3 }\) } So, x = 60º Now, \(\frac{x }{2}\) = \(\frac{ 60º }{2}\) = 30º |
