Two galvanometers have identical characteristics. One of them is converted into a milliammeter and the other into a microammeter. The shunt resistance of microammeter as compared to milliammeter will be:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → more
The formula for shunt resistance $(R_s)$,
$R_s=\frac{R_g}{I-I_g}$
⇒ $R_s$ (microammeter) = 1000 × $R_s$ (milliammeter)
So, the shunt resistance of the microammeter is 1000 times greater than that of milliammeter.