Two galvanometers have identical characteristics. One of them is converted into a milliammeter and the other into a microammeter. The shunt resistance of microammeter as compared to milliammeter will be:

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The correct answer is Option (3) → more

The formula for shunt resistance $(R_s)$,

$R_s=\frac{R_g}{I-I_g}$

⇒ $R_s$ (microammeter) = 1000 × $R_s$ (milliammeter)

So, the shunt resistance of the microammeter is 1000 times greater than that of milliammeter.