x2 + 1/(x^2) = 7 (x > 0), then find the value of x5 + 1/(x^5) .

x² + \(\frac{1}{x^2}\) = 7

(x + \(\frac{1}{x}\)) = \(\sqrt {7\;+\;2}\) =3

x³ + \(\frac{1}{x^3}\) = 27 - 3(3) = 18

Now, x⁵ + \(\frac{1}{x^5}\) = (x² + \(\frac{1}{x^2}\)) (x³ + \(\frac{1}{x^3}\)) - (x + \(\frac{1}{x}\))

= (7 × 18) -3  =  123