If a fair coin is tossed 10 times, find the probability of :
Exactly six heads.
Answer & explanation
Correct answer: option 1
P(X=6) = 10C6(1/2)10 = \(\frac{10!}{6! x 4!}\) \(\frac{1}{210}\)
= 105/512
If a fair coin is tossed 10 times, find the probability of :
Exactly six heads.
Correct answer: option 1
P(X=6) = 10C6(1/2)10 = \(\frac{10!}{6! x 4!}\) \(\frac{1}{210}\)
= 105/512