Practicing Success
If $tan^{-1}\frac{n}{\pi} >\frac{\pi}{4}, $ n ∈ N, then the minimum value of n is |
2 4 6 1 |
4 |
We have $tan^{-1} \frac{n}{\pi} >\frac{\pi}{4}$ $ ⇒ tan^{-1}\frac{n}{\pi} > tan^{-1} 1 $ $[∵\frac{\pi}{4}= tan^{-1} 1]$ $ ⇒ tan\left(tan^{-1}\frac{n}{\pi}\right) > tan \left(tan^{-1} 1\right)$ [∵ tan θ is an increasing function] $ ⇒ \frac{n}{\pi}> 1$ $[∵ tan(tan^{-1}x)=x]$ $ ⇒n > \pi ≅ 3.14 $ $ ⇒n = 4, 5, 6 ........$ Hence, the number value of n is 4. |